Harmonic Analysis Harmonic Analysis VIC circuits are typically driven by non-sinusoidal waveforms (pulses, square waves), which contain harmonics. Understanding how these harmonics interact with the resonant circuit is important for predicting actual performance and potential interference effects. Fourier Analysis Basics Any periodic waveform can be decomposed into a sum of sinusoids: Fourier Series: f(t) = a₀ + Σ[aₙcos(nωt) + bₙsin(nωt)] Where n = 1, 2, 3... are the harmonic numbers (n=1 is fundamental) Harmonic Content of Common Waveforms Square Wave 50% duty cycle square wave contains only odd harmonics: V(t) = (4V pk /π)[sin(ωt) + (1/3)sin(3ωt) + (1/5)sin(5ωt) + ...] Harmonic Frequency Relative Amplitude 1st (fundamental) f 100% 3rd 3f 33.3% 5th 5f 20% 7th 7f 14.3% Pulse Train (Variable Duty Cycle) Pulse train with duty cycle D contains both odd and even harmonics: a n = (2V pk /nπ) × sin(nπD) Effect of Duty Cycle: D = 50%: Only odd harmonics (even harmonics cancel) D = 25%: Strong 2nd harmonic, weak 4th D = 33%: No 3rd harmonic (3rd harmonic null) Narrow pulse: Wide harmonic spectrum, many significant harmonics Resonant Circuit Response to Harmonics A resonant circuit acts as a bandpass filter. It responds most strongly to frequencies near f₀: Response │ │ Fundamental │ ↓ │ ╱╲ │ ╱ ╲ 3rd harmonic │ ╱ ╲ ↓ │ ╱ ╲ (small response) │ ╱ ╲ ┌─┐ │ ╱ ╲ │ │ └───────────────────────────────────────→ f f₀ 3f₀ Response at Harmonic Frequencies: H(nf) = 1 / √[1 + Q²(n - 1/n)²] For high Q circuits, harmonics far from f₀ are strongly attenuated. Example (Q=50, f₀=10 kHz): At 10 kHz (1st): Response = 100% At 30 kHz (3rd): Response ≈ 0.6% At 50 kHz (5th): Response ≈ 0.2% Harmonic Resonance If a harmonic happens to fall near f₀, it can cause problems or opportunities: Scenario Effect Action Drive at f₀ Fundamental resonates Normal operation Drive at f₀/2 2nd harmonic resonates May be useful or problematic Drive at f₀/3 3rd harmonic resonates Subharmonic driving Harmonic hits SRF Choke self-resonates Avoid—causes problems Sub-Harmonic Driving It's possible to drive the circuit at a sub-multiple of f₀ and let a harmonic excite resonance: Example: 3rd Harmonic Drive Circuit resonance: f₀ = 30 kHz Drive frequency: f drive = 10 kHz 3rd harmonic of drive (30 kHz) excites resonance Advantages: Lower switching frequency (easier on semiconductors) Different pulse characteristics May interact differently with WFC Disadvantages: Harmonic has lower amplitude than fundamental Reduced efficiency (energy in unused harmonics) More complex analysis Pulse Shaping for Harmonic Control Adjusting pulse shape can control harmonic content: Technique Effect Slower edges (rise/fall time) Reduces high-order harmonics Duty cycle = 1/n Eliminates nth harmonic Trapezoidal waveform Controlled harmonic rolloff Sine wave drive No harmonics (pure fundamental) Harmonic Interaction with Multiple Resonances In dual-resonant VIC (primary + secondary), harmonics may interact with both: Response │ │ Primary Secondary │ resonance resonance │ ↓ ↓ │ ╱╲ ╱╲ │ ╱ ╲ ╱ ╲ │ ╱ ╲ ╱ ╲ │ ╱ ╲ ╱ ╲ │ ╱ ╲ ╱ ╲ │ ╱ ╲ ╱ ╲ └──────────────────────────────────→ f f₀,pri f₀,sec If f₀,sec = 3 × f₀,pri, then: Fundamental drives primary resonance 3rd harmonic drives secondary resonance This is sometimes called "harmonic matching" Practical Harmonic Considerations EMI Concerns: Harmonics can cause electromagnetic interference. Shield appropriately and consider filtering if needed. Measurement: Use an oscilloscope with FFT function or spectrum analyzer to view harmonic content of your signals. Design Rule: For clean resonance, ensure no significant harmonics fall within the passband (f₀ ± f₀/Q) of unintended resonances. Harmonic Analysis in VIC Matrix Calculator Calculator Feature: The simulation can show frequency response across a range that includes harmonics. When analyzing a design, check whether any harmonics of your drive frequency fall near the circuit's resonant points or SRF values. Next: Transformer Coupling Effects →