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Steam resonator

With this voltage across this plate cell at this frequency, how fast does the water reach the boil — and is it the dipoles or the current doing it?

Loading a circuit fills the slots; change any of them afterwards and the result is your variation on it. All saved circuits.

The parts

A plate cell from the library. Tubes and spheres are not plates; the heating calculation is for a uniform field between plates. About this part.

What is between the plates. Sets its loss at the frequency, its temperature, and its conductivity.

The drive

V

The peak voltage across the plates.

kHz

The frequency of the field.

From the parts

Every number handed to the simulation that you did not type, and where it came from. Each derivation that ran a calculation links to that calculation's page with these numbers in, so it can be checked alone.

Before it can run

  • Spherical - 4x Series 2" & 5" is a spherical cell, and the steam resonator calculation is for plates. Choose a plate cell.
  • w Water 0

    No water chosen; distilled assumed.

  • T Starting temperature 20 °C

    Starting temperature assumed at 20 °C.

  • σ Water conductivity 5 µS/cm

    Conductivity assumed at 5 µS/cm — distilled water — because the water chosen has no dissolved-solids reading.

  • No water chosen, so the cell is taken as full of distilled water at 20 °C. Pick a water to change that.